(4x-2)^(2)-4(4x-2)+3=0

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Solution for (4x-2)^(2)-4(4x-2)+3=0 equation: 



(4x-2)^(2)-4(4x-2)+3=0

We multiply parentheses

(4x-2)^2-16x+8+3=0

We add all the numbers together, and all the variables

-16x+(4x-2)^2+11=0

We move all terms containing x to the left, all other terms to the right

-16x+(4x-2)^2=-11

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